![SOLVED: (5) Calculate the open cell potential, Ecell, if the half-reaction CuzO(s) + HzO(l) + 2 e 2 Cu(s) + 2 OH-(aq) is coupled to a Ag/AgCl reference electrode. Standard conditions apply SOLVED: (5) Calculate the open cell potential, Ecell, if the half-reaction CuzO(s) + HzO(l) + 2 e 2 Cu(s) + 2 OH-(aq) is coupled to a Ag/AgCl reference electrode. Standard conditions apply](https://cdn.numerade.com/ask_images/0121fa032d204bb58cb89af9c167df36.jpg)
SOLVED: (5) Calculate the open cell potential, Ecell, if the half-reaction CuzO(s) + HzO(l) + 2 e 2 Cu(s) + 2 OH-(aq) is coupled to a Ag/AgCl reference electrode. Standard conditions apply
![SOLVED: Salts of hypoiodite ion behave as a weak base, undergoing hydrolysis in water according to the equation: IO- HzO = HIO + OH- Kb for hypoiodite ion 4.37x10-4 Calculate the [H+] SOLVED: Salts of hypoiodite ion behave as a weak base, undergoing hydrolysis in water according to the equation: IO- HzO = HIO + OH- Kb for hypoiodite ion 4.37x10-4 Calculate the [H+]](https://cdn.numerade.com/ask_images/9d80eb482c1a4947a4ffb060669f0832.jpg)
SOLVED: Salts of hypoiodite ion behave as a weak base, undergoing hydrolysis in water according to the equation: IO- HzO = HIO + OH- Kb for hypoiodite ion 4.37x10-4 Calculate the [H+]
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![SOLVED: Hypoiodous acid (HIO) is a weak acid that dissociates in water as follows: HIO(aq) + H2O(l) H3O+(aq) + IO−(aq). A 0.12 M solution of hypoiodous acid has a pH of 5.71. SOLVED: Hypoiodous acid (HIO) is a weak acid that dissociates in water as follows: HIO(aq) + H2O(l) H3O+(aq) + IO−(aq). A 0.12 M solution of hypoiodous acid has a pH of 5.71.](https://cdn.numerade.com/ask_previews/5fc29fe1-1eba-4537-a11a-8c6181e3e675_large.jpg)